The two waves represented by $y_1 = a \sin(\omega t)$ and $y_2 = b \cos(\omega t)$ have a phase difference of

The figure given shows a sinusoidal wave on a string. If the frequency of the wave is $150 \, Hz$,what is the wavelength and velocity of the given wave?

If the wavelength of a wave is $\lambda = 6000 \mathring{A}$,then the wave number will be:

The equation of a wave travelling on a string is $y = \sin(20 \pi x + 10 \pi t)$,where $x$ and $t$ are distance and time in $SI$ units. The minimum distance between two points having the same oscillating speed is (in $cm$)

Velocity of sound waves in air is $V \ m/s$. For a particular sound wave in air,a path difference of $x \ cm$ is equivalent to a phase difference of $n\pi$. The frequency of this wave is:

Two waves are represented by the equations, $y_1 = a \sin(\omega t + kx + 0.57)$ and $y_2 = a \cos(\omega t + kx)$, where $x$ is in metre and $t$ is in second. What is the phase difference between them? $(\pi = 3.14)$